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"semi-regular" should be defined; right now it is not clear what the difference between Johnson and Archimedian solids is. Furthermore, I take it that the platonic solids also count as Archimedian? --Axelboldt I don't think so. semi-regular, i think has to do with the fact that multiple kinds polygons can meet at a vertex And platonic solids are definitely not Archimedean. (since there are five platonic solids, and thirteen archimedean ones....)
A platonic solid is made up of only one type of regular polygon, and is vertex transitive. An Archimedian solid is any vertex transitive solid and is made up of two or more regular polygons. Obviously, these two can't be the same. And a Johnson solid is any solid that is made up of two or more regular polygons, that aren't vertex transitive. Vertex transitive means that any vertex, all the same polygons meet, in the same order and number. Hope that clears it up. Timeroot (talk) 00:33, 24 June 2008 (UTC)
The last sentence uses the term "regular vertex" without defining it. AxelBoldt 09:50, 2 Oct 2003 (UTC)
Found http://www.math.washington.edu/~king/coursedir/m444a03/as/polyhedra-links.html Contains a lot of sections, seems to be in the format of mentioning an Archimedean solid site, someone reviewing it, and selecting their favourite solid. There's at least 2 about this page. I hope copying the comments about this site to here would be considered fair use or something... Κσυπ Cyp 19:15, 18 Jan 2004 (UTC) Jennifer Brosten reviews http://en2.wikipedia.org/en/Archimedean_solid This website was nice because it has the general idea of the Archimedean solids in a rather concise manor though it also offers more in depth information on polyhedras and all of the different Archimedean Polyhedra. The table showing the different Archimedean Polyhedra was well done, because it illustrated the figures while also giving useful information about the vertices, faces and how they meet. The illustrations make it so that you can see the 3D aspect, whereas many sites only show the front without being able to see what is happening at the back of the object as well. The web site does not stop at giving the general information of the different solids. If you click on the names of the solids, you are taken to a new web page which is devoted strictly to that solid.
Mary Moser reviews http://www.ezresult.com/article/Archimedean_solid (Note: That is a not so good mirror of Wikipedia, without working pictures... Ironically, the only complaint about the article is that the pictures don't work.) I was able to find the above website and saw that it had all the basic information presented clearly as well as some interesting history. I really appreciated that throughout the sight vocab words are linked to further definitions and explenations. There is a lot of potential in this sight unfortunately it seems the pages that are supposed to provide images of the polyhedra are not working, (at least I was unable to view them). Also I would like to see descriptions relating them to the platonic solids (essentially how we get the Archimedean polyhedron by truncating the platonic polyhedron). I think a good example of the pictures and information my initial sight is missing can be found at http://www.ul.ie/~cahird/polyhedronmode/favorite.htm. I especially liked the animation showing the truncations for some of the polyhedra. While each of the polyhedra we are discussing is really interesting and fun to explore, the assignment is to choose one favorite so I choose truncated cuboctahedron. It has 26 faces (12 squares, 8 hexagons and 6 octagons), 72 edges, and 48 vertices. Educational toyJovo [1] is a toy that is ideal for constructing Archimedean solids. Can such a link be in the Wikipedia, or is it too commercial? --80.162.63.207 17:01, 5 Feb 2005 (UTC) Inscribed Archimedean polyhedraNOTE: This text for a new and uncompleted section was removed from article!
When the Archimedean polyhedra are inscribed in a sphere, they occupy the following percentages of that sphere's volume:
Here is how you could calculate those percentages: Go onto the page for that solid, and scroll to the part about the cartesian co-ordinates. Take the three numbers, square each of them, and take their sum (for the truncated tetrahedron, these would yield 11, for example). Now take the square root of that. Now, in that same section, it will say "For a side length of --." The truncated tetrahedron, for example, will have "the square root of 8". Divide this side length number by the previous number you got (the square root of 11), and put that into the formula for volume, which will be else where on the page. Now, divide that result of that formula by 4/3pi, and multiply by 100. This is your percentage, and it will work for any Archimedean solid. I already did a few. Timeroot (talk) 17:57, 24 June 2008 (UTC) Wythoff constructionTEST TABLE All the Archimedean solids can be constructed by Wythoff construction of a spherical tiling.
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